$route.ifMin
Check whether the specified route has the lowest number of concurrent sessions.
Syntax:
$route.ifMin( routename, comparename1[, comparenameN] )
Parameters:
routename – the route name to check for
comparename – the route name to compare against.
Returns:
true – if the specified route has the lowest number of concurrent sessions.
false – otherwise
Version Since:
3.8
Example:
$route.ifMin( "gw1", "gw2", "gw3" ) = true
If gw1 has the lowest number of concurrent sessions.